Let me write the article based on real data only.
Data: 大乐透 front area 1-35, 5 numbers per draw. Last 15 draws listed (they say 30 but only 15 given). I must only use given numbers.
Let me compute stats carefully from the 15 draws given.
Draws (new to old): 26120: 1 6 10 15 32 26119: 3 6 20 24 32 26118: 2 9 21 26 32 26117: 4 13 19 29 31 26116: 9 18 22 25 35 26115: 12 20 32 33 35 26114: 8 12 15 29 30 26113: 2 4 6 10 11 26112: 1 3 5 10 22 26111: 10 11 17 26 29 26110: 3 24 25 26 35 26109: 12 14 16 27 34 26108: 1 5 7 21 35 26107: 2 5 7 14 22 26106: 14 17 21 25 28
Frequency counts given: 10(9), 3(7), 14(7), 6(6), 12(6), 26(6), 29(6), 32(6), 33(6), 1(5). Hmm, but from my 15 draws, 10 appears in 26120, 26113, 26112, 26111 = 4 times. The given says 9 times over 30 draws. So the counts are for 30 draws, only 15 listed. I should use the given frequency stats as-is, and be careful about computing my own counts from only 15 draws — that could conflict. Better to reference the given "近30期出现次数最多的号码" list, and use the 15 listed draws for other observations. Actually I need to be careful: any count I compute would be from the 15 listed rows. I can mention "在给定近15期明细中" but that might conflict with 30-period stats. Safer: mostly use the provided frequency list and describe recent 15 draws qualitatively without precise counts that contradict.
Let me compute tail numbers (尾数) — the 选题 mentions "前区尾数最大数邻期和走势图" which is an odd composite phrase. I'll interpret: 前区尾数分布、尾数和值、大小奇偶、质合、012路、分区.
Let me compute per-draw stats from the 15 rows:
26120: 1 6 10 15 32 → sum 64, odd/even: 1,15 odd; 6,10,32 even → 2奇3偶. 尾数: 1,6,0,5,2 → 尾和 14, 最大尾 6. 分区: 1-7:1,6 (2); 8-14:10 (1); 15-21:15 (1); 22-28:0; 29-35:32 (1). Actually standard 大乐透 前区三分区 1-12,13-24,25-35 or 五分区 1-7,8-14,15-21,22-28,29-35.
Let me compute a few useful things:
Sum of last draw 64 (small). 26119: 3+6+20+24+32 = 85 26118: 2+9+21+26+32 = 90 26117: 4+13+19+29+31 = 96 26116: 9+18+22+25+35 = 109 26115: 12+20+32+33+35 = 132 26114: 8+12+15+29+30 = 94 26113: 2+4+6+10+11 = 33 26112: 1+3+5+10+22 = 41 26111: 10+11+17+26+29 = 93 26110: 3+24+25+26+35 = 113 26109: 12+14+16+27+34 = 103 26108: 1+5+7+21+35 = 69 26107: 2+5+7+14+22 = 50 26106: 14+17+21+25+28 = 105
Sums range 33-132. Average of these 15: let's sum: 64+85=149; +90=239; +96=335; +109=444; +132=576; +94=670; +33=703; +41=744; +93=837; +113=950; +103=1053; +69=1122; +50=1172; +105=1277. 1277/15 ≈ 85.1.
Last draw sum 64 is below that average; 上期 64，前两期 85、90 — 近期和值偏低 (64,85,90,96).
Tail analysis: 上期尾数 1,6,0,5,2 — 尾数最大 6, 尾数和 14. 26119 尾: 3,6,0,4,2 → max 6, sum 15 26118: 2,9,1,6,2 → max 9, sum 20 26117: 4,3,9,9,1 → max 9, sum 26 26116: 9,8,2,5,5 → max 9, sum 29 26115: 2,0,2,3,5 → max 5, sum 12 26114: 8,2,5,9,0 → max 9, sum 24 26113: 2,4,6,0,1 → max 6, sum 13 26112: 1,3,5,0,2 → max 5, sum 11 26111: 0,1,7,6,9 → max 9, sum 23 26110: 3,4,5,6,5 → max 6, sum 23 26109: 2,4,6,7,4 → max 7, sum 23 26108: 1,5,7,1,5 → max 7, sum 19 26107: 2,5,7,4,2 → max 7, sum 20 26106: 4,7,1,5,8 → max 8, sum 25
尾数最大数序列(新→旧): 6,6,9,9,9,5,9,6,5,9,6,7,7,7,8. 邻期和 of 最大尾: 上期6 + 前一期6 = 12; 6+9=15; 9+9=18; 9+9=18; 9+5=14...
I can mention: 近5期最大尾数为 6、6、9、9、9（新→旧）；邻期和 12、15、18、18、14。
Duplicate tails: 上期尾数 1,6,0,5,2 全部不同 (0-9 unique). 26119: 3,6,0,4,2 全不同. 26118: 2,9,1,6,2 → 尾2重复. 26117: 4,3,9,9,1 → 尾9重复. 26116: 5重复. 26115: 2重复. 26114: 2重复. 26113: 全不同. 26112: 全不同. 26111: 1重复... Let me count 重尾情况: 15期中出现重尾的: 26118(2), 26117(9), 26116(5), 26115(2), 26114(2), 26111(1), 26110(5), 26109(4), 26108(1,5 两次?), 26108: 1,5,7,1,5 → 1 and 5 both repeated. 26107: 2 repeat. So 11 of 15 have 重尾? Let me check the no-repeat ones: 26120, 26119, 26113, 26112, 26106? 26106: 4,7,1,5,8 all distinct → yes distinct. So distinct: 26120, 26119, 26113, 26112, 26106 = 5 draws. Repeat: 10 draws. Good: "近15期中有10期出现同尾号".
奇偶比: 26120: 1,15 odd (2奇3偶) — wait 6,10,32 even =3 even. 2:3 26119: 3 odd, 6,20,24,32 even → 1:4 26118: 9,21 odd; 2,26,32 even → 2:3 26117: 13,19,29,31 odd; 4 even → 4:1 26116: 9,25,35 odd; 18,22 even → 3:2 26115: 33,35 odd; 12,20,32 even → 2:3 26114: 15,29 odd; 8,12,30 even → 2:3 26113: 11 odd; 2,4,6,10 even → 1:4 26112: 1,3,5 odd; 10,22 even → 3:2 26111: 11,17,29 odd; 10,26 even → 3:2 26110: 3,25,35 odd; 24,26 even → 3:2 26109: 27 odd; 12,14,16,34 even → 1:4 26108: 1,5,7,21,35 all odd → 5:0 26107: 5,7 odd; 2,14,22 even → 2:3 26106: 17,21,25 odd; 14,28 even → 3:2
Count 奇:偶 分布: 3:2 appears 26116,26112,26111,26110,26106 = 5次; 2:3 appears 26120,26118,26115,26114,26107 = 5次; 1:4: 26119,26113,26109 = 3; 4:1: 26117 =1; 5:0: 26108 = 1.
大小 (1-17 small, 18-35 big): 26120: 1,6,10,15 small (4); 32 big (1) → 4小1大 26119: 3,6 small; 20,24,32 big → 2小3大 26118: 2,9 small; 21,26,32 big → 2:3 26117: 4,13 small; 19,29,31 big → 2:3 26116: 9 small; 18,22,25,35 big → 1小4大 26115: 12 small; 20,32,33,35 big → 1:4 26114: 8,12,15 small; 29,30 big → 3:2 26113: 2,4,6,10 small; 11 small too → 5小0大 26112: 1,3,5,10 small; 22 big → 4:1 26111: 10,11,17 small; 26,29 big → 3:2 26110: 3 small; 24,25,26,35 big → 1:4 26109: 12,14,16 small; 27,34 big → 3:2 26108: 1,5,7 small; 21,35 big → 3:2 26107: 2,5,7,14 small; 22 big → 4:1 26106: 14,17 small; 21,25,28 big → 2:3
质合: primes in 1-35: 2,3,5,7,11,13,17,19,23,29,31. 1 is neither (usually 1 treated as 既非质也非合 in 大乐透 analysis, but often counted as 合? Usually 质数合数排除1). I'll treat 1 as non-prime (合/特殊) — better to just say 质数个数.
26120: numbers 1,6,10,15,32 → primes: none (1 not prime) → 0质5合 26119: 3 prime; 6,20,24,32 → 1质 26118: 2; 9,21,26,32 → 1质 26117: 13,19,29,31 → 4质1合 (4) 26116: 9,18,22,25,35 → 0质 26115: 12,20,32,33,35 → 0质 26114: 29 → 1质 26113: 2,11 → 2质 26112: 3,5 → 2质 (1 not) 26111: 11,17,29 → 3质 26110: 3 → 1质 26109: none? 12,14,16,27,34 → 0质 26108: 5,7 → 2质 26107: 2,5,7 → 3质 26106: 17 → 1质
012路 (mod 3): 26120: 1(1),6(0),10(1),15(0),32(2) → 0路2,1路2,2路1 26119: 3(0),6(0),20(2),24(0),32(2) → 0路3,1路0,2路2 26118: 2(2),9(0),21(0),26(2),32(2) → 0:2,2:3,1:0 26117: 4(1),13(1),19(1),29(2),31(1) → 1路4,2路1,0路0 26116: 9(0),18(0),22(1),25(1),35(2